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Class 9
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Maths
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Triangles
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Easy Questions
Triangles
Maths
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In
$ΔABC$
and
$ΔDEF$
, AB = DF and
$∠A=∠D$
. The two triangles will be congruent by SAS axiom if :
A
BC = EF
B
AC = DE
C
BC = DE
D
AC = EF
Easy
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>
In
$ΔPQR,∠P=60_{∘}$
and
$∠Q=50_{∘}$
. Which side of the triangle is the longest ?
A
PQ
B
QR
C
PR
D
None
Easy
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>
In the given figure , which of the following statement is true ?
A
$∠B=∠C$
B
$∠B$
is the greatest angle in triangle
C
$∠B$
is the smallest angle in triangle
D
$∠A$
is the smallest angle in triangle
Easy
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>
If
$ΔABC≅ΔDEF$
by SSS congruence rule then :
A
$AB=EF,BC=FD,CA=DE$
B
$AB=FD,BC=DE,CA=EF$
C
$AB=DE,BC=EF,CA=FD$
D
$AB=DE,BC=EF,∠C=∠F$
Easy
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>
In
$ΔABC,∠B=30_{∘},∠C=80_{∘}$
and
$∠A=70_{∘}$
then,
A
$AB>BC<AC$
B
$AB<BC>AC$
C
$AB>BC>AC$
D
$AB<BC<AC$
Easy
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>
In triangles ABC and DEF, AB
$=$
FD and
$∠A=∠D$
. The two triangles will be congruent by
SAS axiom if :
A
BC
$=$
EF
B
AC
$=$
DE
C
AC
$=$
EF
D
BC
$=$
DE
Easy
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>
In
$ΔPQR,$
if
$∠R>∠Q,$
then:
A
$QR>PR$
B
$PQ>PR$
C
$PQ<PR$
D
$QR<PR$
Easy
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>
The construction of a triangle ABC, given that BC = 3 cm is possible when difference of AB and AC is equal to :
A
3.2 cm
B
3.1 cm
C
3 cm
D
2.8 cm
Easy
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>
ABC is an isosceles triangle with AB
$=$
AC and D is a point on BC such that
$AD⊥BC$
(Fig. 7.13). To prove that
$∠BAD=∠CAD,$
a student proceeded as follows:
$ΔABD$
and
$ΔACD,$
AB
$=$
AC (Given)
$∠B=∠C$
(because AB
$=$
AC)
and
$∠ADB=∠ADC$
Therefore,
$ΔABD≅ΔACD(AAS)$
So,
$∠BAD=∠CAD(CPCT)$
What is the defect in the above arguments?
A
It is defective to use
$∠ABD=∠ACD$
for proving this result.
B
It is defective to use
$∠ADB=∠ADC$
for proving this result.
C
It is defective to use
$∠BAD=∠DCA$
for proving this result.
D
Cannot be determined
Easy
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>
Given
$ΔOAP≅ΔOBP$
in figure, the criteria by which the triangles are congruent is:
A
$SAS$
B
$SSS$
C
$RHS$
D
$ASA$
Easy
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>